Fibonacci and squares

Algebra Level 4

The Fibonacci sequence ( F n ) (F_n) is defined as: F 1 = 1 , F 2 = 1 , F n = F n 1 + F n 2 for n 3. F_1 = 1,\ F_2 = 1,\ F_n = F_{n-1} + F_{n-2}\ \text{for}\ n \geq 3.

Find the sum of all positive integers n n such that F n = n 2 F_n=n^2 .


The answer is 13.

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1 solution

We will prove that F n > n 2 F_n>n^2 for all n 13 n\ge13 by induction ( ) (*) .

For n = 13 n=13 and n = 14 n=14 , ( ) (*) is true, since F 13 = 233 , F 14 = 377 F_{13}=233,F_{14}=377 .

Suppose ( ) (*) is true for some n = k n=k and n = k + 1 n=k+1 with k 13 k \ge 13 .

We need prove that ( ) (*) is true for n = k + 2 n = k + 2 .

We have: F k + 2 = F k + 1 + F k > ( k + 1 ) 2 + k 2 = 2 k 2 + 2 k + 1 = ( k + 2 ) 2 + ( k 3 ) ( k + 1 ) > ( k + 2 ) 2 F_{k+2}=F_{k+1}+F_k>(k+1)^2+k^2=2k^2+2k+1=(k+2)^2+(k-3)(k+1)>(k+2)^2 .

So, F n > n 2 F_n>n^2 for all n 13 n\ge13 .

Consider n 12 n\le 12 , we get only 2 solutions, which are F 1 = 1 F_1=1 and F 12 = 144 F_{12}=144 .

Hence, the answer is: 1 + 12 = 13 1+12=\boxed{13} .

this is completely hit and trial at 2nd last step

Md Zuhair - 4 years, 4 months ago

We dont get any general equation, by which we get the value, But yes, It is a good sum

Md Zuhair - 4 years, 4 months ago

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