The Fibonacci sequence is defined as:
Find the sum of all positive integers such that .
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We will prove that F n > n 2 for all n ≥ 1 3 by induction ( ∗ ) .
For n = 1 3 and n = 1 4 , ( ∗ ) is true, since F 1 3 = 2 3 3 , F 1 4 = 3 7 7 .
Suppose ( ∗ ) is true for some n = k and n = k + 1 with k ≥ 1 3 .
We need prove that ( ∗ ) is true for n = k + 2 .
We have: F k + 2 = F k + 1 + F k > ( k + 1 ) 2 + k 2 = 2 k 2 + 2 k + 1 = ( k + 2 ) 2 + ( k − 3 ) ( k + 1 ) > ( k + 2 ) 2 .
So, F n > n 2 for all n ≥ 1 3 .
Consider n ≤ 1 2 , we get only 2 solutions, which are F 1 = 1 and F 1 2 = 1 4 4 .
Hence, the answer is: 1 + 1 2 = 1 3 .