Fibonacci Game

Logic Level 2

Hans picked two consecutive positive integers.

He called the smaller number the first term then the other, the second term.
He added the two numbers together and called the sum the third term.
He added the third term and the second term and the result would be the fourth term, and so on.

Hans' seventh term is $86$ . Multiply Hans' two starting numbers.

Join the guessing game!

The answer is 42.

1 solution

Kaizen Cyrus
Aug 6, 2020

$\small \underbrace{x}_{1\text{st term}}, \underbrace{x+1}_{2\text{nd}}, \underbrace{2x+1}_{3\text{rd}}, \underbrace{3x+2}_{4\text{th}}, \underbrace{5x+3}_{5\text{th}}, \underbrace{8x+5}_{6\text{th}}, \underbrace{13x + 8}_{7\text{th}}, ...$

$\begin{aligned} 13x + 8 &= 86 \\ x &= 6 \end{aligned}$

The product of $6$ and $7$ is $\boxed{42}$ .

$42$ is always the answer. :)

Vinayak Srivastava - 10 months, 1 week ago

I forgot the 2 numbers chosen were consecutive and use 8x+13y=86 to get x=14, y=2 (rej) and x=6, y=7

Kenny O. - 10 months, 1 week ago

Fibonacci Game

The answer is 42.

1 solution

0 pending reports