Fibonacci Iterations.

Algebra Level 3

There exist unique positive integers n 1 , n 2 , n 3 , n 4 , n 5 , n 6 n_1, n_2, n_3, n_4, n_5, n_6 such that

i 1 = 0 100 i 2 = 0 100 i 3 = 0 100 i 4 = 0 100 i 5 = 0 100 F i 1 + i 2 + i 3 + i 4 + i 5 = F n 1 5 F n 2 + 10 F n 3 10 F n 4 + 5 F n 5 F n 6 \large\ \displaystyle \sum _{ { i }_{ 1 } = 0 }^{ 100 }{ \sum _{ { i }_{ 2 } = 0 }^{ 100 }{ \sum _{ { i }_{ 3 } = 0 }^{ 100 }{ \sum _{ { i }_{ 4 } = 0 }^{ 100 }{ \sum _{ { i }_{ 5 } = 0 }^{ 100 }{ { F }_{ { i }_{ 1 } + { i }_{ 2 } + { i }_{ 3 } + { i }_{ 4 } + { i }_{ 5 } } } } } } } = { F }_{ { n }_{ 1 } } - 5{ F }_{ { n }_{ 2 } } + 10{ F }_{ { n }_{ 3 } } - 10{ F }_{ { n }_{ 4 } } + 5{ F }_{ { n }_{ 5 } } - { F }_{ { n }_{ 6 } }

where F n F_n is the Fibonacci Number with F 0 = 0 , F 1 = 1 F_0 = 0, F_1 = 1 .

Find n 1 + n 2 + n 3 + n 4 + n 5 + n 6 n_1 + n_2 + n_3 + n_4 + n_5 + n_6 .


The answer is 1545.

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