Fibonacci Sequence...and a Triangle?

Let a,b, and c be the lengths of the sides of the Triangle. If the lengths are terms of the Fibonacci Sequence, then $a+b=c$ . Since the semiperimeter is $144$ , and the perimeter is twice the semiperimeter, $144*2=288$ which is the perimeter. As a result, $a+b+c=288$ . Since $a+b=c$ , substituting for $c$ we get $a+b+a+b=288$ . This simplifies to $a+b=144$ . Because $a+b=c$ , $c=144$ . As a result, the third side of the triangle is equal to the sum of the other two, so the triangle is degenerate. In this case, it will be a line segment. The length of the segment is $144$ and the height is $0$ , so $(0.5)*(144)*(0)=0$ , which is the area of the triangle. Note: $(*)$ represents multiplication.