Fibonacci Squared

F n F_{n} denotes the n t h n^{th} term of the Fibonacci sequence where F 1 = 1 F_{1} = 1 and F 2 = 1 F_{2} = 1 .

Given that F 14 = 377 F_{14} = 377 and F 15 = 610 F_{15} = 610

What is the value of n = 1 15 \displaystyle \sum_{n=1}^{15} ( F n 2 ) ({F_{n}}^2)


The answer is 602070.

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1 solution

knowing

F n F n 1 = ( F n 1 + F n 2 ) F n 1 = F n 1 2 + F n 2 F n 1 F_nF_{n-1}=(F_{n-1}+F_{n-2})F_{n-1}=F^2_{n-1}+F_{n-2}F_{n-1}

we recursively get

F n F n 1 = F n 1 2 + + F 2 2 + F 2 F 1 = F n 1 2 + + F 2 2 + F 1 2 = k = 1 n 1 F k 2 F_{n}F_{n-1}=F^2_{n-1}+\dots+F_2^2+F_2F_1=F^2_{n-1}+\dots+F_2^2+F^2_1=\sum_{k=1}^{n-1}F^2_k

Take n = 16 n=16 to have

F 16 F 15 = k = 1 15 F k 2 F_{16}F_{15}=\sum_{k=1}^{15}F^2_k

F 16 F 15 = ( F 15 + F 14 ) F 15 = 987 × 610 = 602070 F_{16}F_{15}=(F_{15}+F_{14})F_{15}=987 \times 610=602070

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