Fibonacci squares?

Number Theory Level pending

The Fibonacci numbers are given by:

0 , 1 , 1 , 2 , 3 , 5 , 8 , 13 , 21.... 0,1,1,2,3,5,8,13,21....

And in general they satisfy the following recursion relation:

  • F ( 0 ) = 0 F(0) = 0
  • F ( 1 ) = 1 F(1) = 1
  • F ( n ) = F ( n 2 ) + F ( n 1 ) F(n) = F(n-2) + F(n-1) for n > 1 n > 1

For how many Fibonacci numbers does F ( n ) = n 2 F(n) = n^2 ?

3 None of these 4 2 0 1 \infty 5

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1 solution

Geoff Pilling
Nov 24, 2016

F ( n ) = n 2 F(n) = n^2 for only 3 \boxed3 values of n n , namely 0 0 , 1 1 , and 12 12 .

There are none greater than 12 12 , since the Fibonacci sequence increases much faster than n 2 n^2 for n > 12 n>12 .

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