Finally, it leaves some remainder

We factorise 153 to two coprimes 153=17 X 9

${ 128 }^{ 1000 }\equiv { 9 }^{ 1000 }\equiv { 3 }^{ 2000 }\equiv { 3 }^{ 125*16 }\equiv { 3 }^{ 125*\varphi (17) }\equiv 1\quad (mod\quad 17)\\ { 128 }^{ 1000 }\equiv 2^{ 1000 }\equiv { ({ 2 }^{ 3 }) }^{ 333 }.(2)\quad \equiv (-1)^{ 333 }.(2)\equiv -2\equiv 7\quad (mod\quad 9)\quad$

Now apply CRT to get answer

${ 128 }^{ 1000 }\equiv 52mod153$