Find

Calculus Level pending

t n = n 5 + n 3 n 4 + n 2 + 1 t_n = \dfrac{n^5 + n^3}{n^4 + n^2 + 1} - This is the nth term of a sequence

If sum of its n terms can be expressed as S n = a n 2 + a + 1 b n 2 + b S_{n} = a_n^2 + a + \dfrac{1}{b_n^2 + b}

Find a n b n + a + b \dfrac{a_n}{b_n} + a + b

Note - a and b are fractions expressed in the smallest ratio.


The answer is 1.375.

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