are positive integers such that
are all powers of 2. Determine the total number of unordered triplets .
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A small computer search yields ( 2 , 2 , 2 ) , ( 2 , 2 , 3 ) , ( 2 , 6 , 1 1 ) , ( 3 , 5 , 7 ) , but I have no idea whether these are the only solutions. Anyone?
Edit: this is a 2015 IMO problem, and seems extremely difficult! Here is what appears to be a full solution.