Find each value

Algebra Level 2

a b c 'abc' represents a three digit number where a , b , c a, b, c are the digits of it and b c 'bc' also represents a two digit number where b b and c c are the digits of it. If a b c = ( b c ) 2 abc=(bc)^2 and b c = c 2 bc=c^2 , then which digits are represented by a , b , c a, b, c ?


This problem is a part of the set Problems for everyone!!!

a = 7 ; b = 6 ; c = 5 a=7; b=6; c=5 a = 6 ; b = 5 ; c = 2 a=6; b=5; c=2 a = 6 ; b = 2 ; c = 5 a=6; b=2; c=5 a = 4 ; b = 5 ; c = 6 a=4; b=5; c=6

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1 solution

S P
May 24, 2018

It is given that b c = c 2 bc=c^2

Hence, c = 5 or 6 c=5 ~ \text{or} ~ 6 because any power of 5 and 6 5 ~ \text{and} ~ 6 has units digit as 5 and 6 5 ~ \text{and} ~ 6 which we want

b = 2 or 3 \therefore b=2~\text{or}~3 because 5 2 = 25 and 6 2 = 36 5^2=25~\text{and}~ 6^2=36

Now we are given a b c = ( b c ) 2 abc=(bc)^2 and 2 5 2 = 625 and 3 6 2 = 1296 25^2=625~\text{and}~36^2=1296

Since, ( b c ) 2 (bc)^2 must be a three digit number b c = 25 bc=25 and a = 6 a=6

Hence, a = 6 ; b = 2 ; c = 5 \boxed{a=6;b=2;c=5}

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