find the number of integer values of x for which the function is a prime number
f(x) =
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we can see that 1 is the root of the equation
therefore when dividing the polynomial with (x -1)
we get
( x − 1 ) ( x 2 − 7 x + 1 3 ) = f(x)
thus for f(x) to be a prime number we should have
( x − 1 ) ( x 2 − 7 x + 1 3 ) = 1
thus
(x -1 )= 1 or (x -3)(x - 4) = 1
therefore 3 solutions