find its remainder if you can?

By adding 2 to the number, it is divisible by both 5 and 3 and hence divisible by 15. So, when subtracting 2 to get back the original number, a remainder of 15-2 = 13 is obtained.

we need to find out first the unit place of the number ,then the next to second digitplace so as to get remainders as 3 and 1 ,thus we reach to number 13,where when we devide by 5 and 3 will get remainder 3 and 1 respectively.now,we go to third digit place and see that by dividing by 5 and 3 we get desired remainders 3 an1.thereby we reach the number 313.when we divide this number by 15,remainder is 13 Ans. K.K.GARG,India

It's very easy. When a number in being divided by 5 leaves a remainder of 3, it is either ending with 3 or (5+3). However, if it ends with 3, the multiple of 3 that gives a remainder of 1 on dividing a number ending by 3 is that multiple which ends with 4. However, we know that 4 is not among {3,5}, so we discard it. Similarly, a multiple of 3 near 8 is that multiple which ends with 7. Hence we consider the first multiple of 3 ending with 7, that being 27. Add one to it and divide by 15. We get a remaimder of 13. Thats the answer.

Alternative There is another method for this but i dont remember it. Its shorter. Pls post it if u know it.

Thank You