Find minimum

Algebra Level 2

Find minimum of the expression: x 2 + y 2 x^{2}+y^{2} in which: x 2 + y 2 = 4 × x × y . x^{2}+y^{2} = 4 \times x \times y.


The answer is 0.

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2 solutions

Zekki Keyman
Sep 6, 2014

x^2+y^2>=0 with all x,y. the "=" happen when x=y=0

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its X^2 + Y^2....squares are always +ve... this means to have a min value of two squares...both of them have to be simultaneously = 0 this means 0+0=0 min value is"0"

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