Find No. ??
Level
pending
Find the sum of all three digit numbers which leave the remainder 3 when divided by 5?
The answer is 99090.
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1 solution
the first number will be 103 second number will be 108 (103+5) as 5 is the common difference third number 113 (103+2*5) ...................... last number of the series will be 998 (995+3) now total number = n An = a+(n-1)d 998= 103+(n-1)5 895=(n-1)5 n=179+1 =180
now Sn = n/2 {2a+(n-1)d} Sn =180/2{2 103+(180-1)5} sn= 90{206+895} Sn=1101 90 =99090 = answer