A geometry problem by Aly Ahmed

Geometry Level 3

5 sin x cos x + 5 cos x sin x = 2 ( sin x + cos x ) 5^{\sin x - \cos x} + 5^{\cos x - \sin x} = \sqrt2 (\sin x + \cos x)

Find x x (in degrees) in the range 0 x 9 0 0^\circ \leq x \leq 90^\circ satisfying the equation above.


The answer is 45.

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1 solution

L. H. S. is 2 5 sin x cos x × 5 cos x sin x \geq 2 \sqrt {5^{\sin x-\cos x}\times 5^{\cos x-\sin x}} or 2 \geq 2 . R. H. S. is 2 sin ( x + π 4 ) 2 2\sin \left(x+\dfrac{π}{4}\right) \leq 2 . So the only solution is the value of x x for which each side of the equation is 2 2 . This happens when x = 45 ° x=\boxed {45\degree} .

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