Find only one share

Algebra Level 2

Alex, Bond and Cal run a business together, and share the money as a b = b c = 3 4 \dfrac{a}{b} = \dfrac{b}{c} = \dfrac{3}{4} where, a a is Alex's share, b b is Bond's share, and c c is Cal's share.

Now, $370 is to be shared among them. What is Alex's share (in $)?


The answer is 90.

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2 solutions

{ a b = 3 4 b = 4 3 a b c = 3 4 c = 4 3 b = 16 9 a \begin{cases} \dfrac ab = \dfrac 34 & \implies b = \dfrac 43a \\ \dfrac bc = \dfrac 34 & \implies c = \dfrac 43b = \dfrac {16}9a \end{cases}

We know that

a + b + c = 1 ( 1 + 4 3 + 16 9 ) a = 1 37 9 a = 1 a = 9 37 \begin{aligned} a+b+c=1 \\ \left(1+\frac 43 + \frac {16}9 \right)a & = 1 \\ \frac {37}9a & = 1 \\ \implies a & = \frac 9{37} \end{aligned}

Therefore, Alex's share of $370 is $ 370 × a = $ 370 × 9 37 = $ 90 \$370 \times a = \$370 \times \dfrac 9{37} = \$\boxed{90} .

Munem Shahriar
Jul 8, 2017

Lets work out everything in terms of " b b " (Bond's share) first,

a b \dfrac{a}{b} = = b c \dfrac{b}{c} = = 3 4 \dfrac{3}{4}

a b \dfrac{a}{b} = = 3 4 \dfrac{3}{4} a = \Rightarrow a = 3 4 \dfrac{3}{4} b b

b c \dfrac{b}{c} = = 3 4 \dfrac{3}{4} \Rightarrow c b \dfrac{c}{b} = = 4 3 \dfrac{4}{3} c = 4 3 b \Rightarrow c = \dfrac 43b

The total amount to be divided is $ 370 \$370 . So,

\Rightarrow 3 4 b + \dfrac 34b + b + b + 4 3 b \dfrac 43b = 370 = 370

\Rightarrow ( 9 b + 12 b + 16 b ) 12 \dfrac{(9b + 12b + 16b)}{12} = 370 = 370

\Rightarrow 37 b 12 \dfrac{37b}{12} = 370 = 370

37 b = 4440 \Rightarrow 37b = 4440 ;[Multiplying 370 370 with 12 12 ]

b = 120 ∴ b = 120

Now we know that Bond's share is 120 120

So, Alex's share a = \Rightarrow a = 3 4 \dfrac{3}{4} × 120 \times 120 = 90 = 90

Therefore a = $ 90 a = \$90

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