The sum of two digit number is 9. Also, 9 times this number is twice the number obtained by reversing the order of digits of the number. Find the number.
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t = t e n s d i g i t
u = u n i t s d i g i t
t + u = 9 (equation 1)
9 ( 1 0 t + u ) = 2 ( 1 0 u + t ) (equation 2)
Solving the system of equations gives t = 1 and u = 8 .
So the answer is 1 8 .