Two circles of unit radii touch each other and each of them touches internally a circle of radius two,as shown in figure. The radius of the circle which touches all three circles is __________ .
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I used the same method....
By pythagorean theorem, we have
( r + 1 ) 2 = h 2 + 1
r 2 + 2 r + 1 = h 2 + 1
r 2 + 2 r = h 2
h = r 2 + 2 r
Hence,
2 = h + r = r 2 + 2 r + r
2 − r = r 2 + 2 r
Square both sides.
( 2 − r ) 2 = ( r 2 + 2 r ) 2
4 − 4 r + r 2 = r 2 + 2 r
4 = 2 r + 4 r
r = 3 2 ≈ 0 . 6 6 6 6 7
drop perpendicular from O to AB as D
OB = 1+r
DB =1
so find OD
and OD + r=2
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