Find remainder

$216^{41} \equiv (217-1)^{41} \equiv -1 \equiv \boxed {216} \pmod {217}$

${ 216 }^{ 2 }\equiv 1\quad (mod\quad 217)$

${ 216 }^{ 41 }={ ({ 216 }^{ 2 }) }^{ 20 }\cdot 216\equiv 1\cdot 216\quad (mod\quad 217)$

Remainder: $\boxed{216}$