Find s i n θ sin\theta

Level pending

If

2 s i n θ = 2 c o s θ 2sin\theta =2-cos\theta

find s i n θ sin\theta

-3/5 1 or 3/5 -1 or 1 Cannot say

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1 solution

Soumo Mukherjee
Oct 17, 2014

c o s θ = 2 2 s i n θ 1 sin 2 θ = 2 2 s i n θ 5 sin 2 θ 8 s i n θ + 3 = 0 s i n θ = 1 o r 3 / 5 \displaystyle cos{ \theta }=2-2sin\theta \\ \Rightarrow \sqrt { 1-\sin ^{ 2 }{ \theta } } =2-2sin\theta \\ \Rightarrow 5\sin ^{ 2 }{ \theta } -8sin{ \theta }+3=0\\ \Rightarrow sin{ \theta }=1\quad or\quad 3/5

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