Find t

Algebra Level 3

At ' t t ' minutes past 2 PM the time needed by the minutes hand of a clock to show 3 PM was found to be 3 minutes less than t 2 4 \dfrac{t^2}{4} minutes.Find the value of t t .

13 9 4 14 10

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1 solution

Its from Ncert exampler class 10.

\rightarrow This can be translated as 60 t = t 2 4 3 240 4 t = t 2 12 t 2 + 4 t 252 = ( t + 18 ) ( t 14 ) = 0. 60 - t = \dfrac{t^{2}}{4} - 3 \Longrightarrow 240 - 4t = t^{2} - 12 \Longrightarrow t^{2} + 4t - 252 = (t + 18)(t - 14) = 0.

Since we require that t > 0 t \gt 0 we find that t = 14 t = 14 minutes.

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