Find The Acceleration

Level 2

The velocity of a particle is: v ( s ) = 3 s + 4 2 s + 1 , v(s) = \frac{3s + 4}{2s + 1}, where s is the distance traveled.

What is the acceleration of the particle when s = 2 s = 2 ?


The answer is -0.40.

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1 solution

Tristan Goodman
Apr 20, 2019

Multiply the expression for "v" in terms of position (the problem states "distance traveled" but I think "position" is a little more appropriate in this context so that's why I'm calling it that) by its own derivative to get acceleration in terms of position, since (dv/ds) (ds/dt)=dv/dt; which can also be written as (dv/ds) v=dv/dt.

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