find the angle
Geometry
Level
1
If the angle ∠DGB is twice the angle ∠DBG. find the angle ∠CAG.......
The answer is 40.
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1 solution
As ∠DGB is twice ∠DBG, the ∠DBG must be 40° and ∠DGB must be 80°.
So the angle ∠CGA will also be 80°.
Again from the circle we get ∠GCA = ∠ GDB = 60°.
As the summation of all angle of triangle ACG is 180°. we get ∠CAG = 40°