Find The Angle

Geometry Level 3

A point P lies on the circle $x^{2} + y^{2} = 169$ . If Q = (5, 12) and R = (-12, 5) , then the angle $\angle QPR$ is

\pi/3

\pi/4

\pi/6

\pi/2

1 solution

Suyash Mittal
Apr 24, 2014

Q = (5, 12) ; R = (-12, 5) ; O = (0, 0) ${ m }_{ OQ }\quad =\quad \frac { 12 }{ 5 } \quad ,\quad { m }_{ OR }\quad =\quad \frac { 5 }{ -12 }$ ${ m }_{ OQ }\quad *\quad { m }_{ OR }\quad = \quad-1$ so ${ \angle }QOR\quad =\quad \pi /2$ Hence $\angle QPR\quad =\quad \pi /4$

Find The Angle

1 solution

0 pending reports