A
rectangle is inside circle
. Two of its vertices lies on the diameter and the other lies on the circumference of the circle. Find the area outside the rectangle but inside the circle. Use
for the approximation of
.
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Notice that the diagonal of the rectangle is the radius of the circle. Let r be the diagonal of the rectangle. Then r 2 = 5 2 + 9 2 = 1 0 6 . The area desired is area of the circle minus the area of the rectangle, we have
π r 2 − 5 ( 9 ) = 3 . 1 4 ( 1 0 6 ) − 4 5 = 2 8 7 . 8 4