Find the base

If n is the base, then the meaning of the equation (in decimal) is:

$(6n+2)\cdot(3n+2)=1n^3+1n^2+0n+4\iff$

$\iff18n^2+12n+6n+4=n^3+n^2+4\iff$

$\iff n^3-17n^2-18n=0\iff$

$\iff n(n^2-17n-18)=0\iff$

$\iff n(n^2-18n+n-18)=0\iff$

$\iff n(n-18)(n+1)=0$

The solutions of the equation are n=0, n=18 and n=-1.

The only acceptable solution is n=18.