Find the coefficient of friction.

A solid hemisphere of weight P rests with its curved surface in contact with a rough inclined plane. A weight Q is placed at some point on the rim of the hemisphere to keep its plane surface horizontal then its minimum coefficient of friction is -

Q/root(P(Q+2P)) P-Q/root(P(+2Q)) P+Q/root(P(P+2Q)) Q/root(P(P+2Q))

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1 solution

Sudipan Mallick
May 6, 2014

Draw the free body diagram. At the point where the hemisphere is touching the plane- P(Rsin thita)=Q(1-sin thita)R {where thita is the angle of friction}. sin thita=Q/(P+Q) so coefficient of friction=tan thita=Q/root(P(P+2Q))

My answer was correct but it’s showing wrong

Babaji Rocks - 8 months, 1 week ago

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