A B C D is square and C is the center of the circle. Given that C E = 1 0 cm and D E C is a triangle. Find the area of the shaded region (in cm 2 ).
Give your answer to 2 decimal places.
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Area = Area of circle − area of pie slice D C F − area of triangle D E C .
Area = 1 0 0 π − 3 6 0 4 5 ⋅ 1 0 0 π − 2 ⋅ 2 1 ⋅ 1 0 s i n ( 2 2 . 5 ) ⋅ 1 0 c o s ( 2 2 . 5 ) = 2 3 9 . 5 3
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The area of the shaded region is equal to the area of a semicircle plus the area of a circular segment. The area of the semicircle is 2 1 π ( 1 0 2 ) ≈ 1 5 7 . 0 8 . The area of the circular segment is equal to the area of the circular sector minus the area of the triangle, we have 3 6 0 1 3 5 ( π ) ( 1 0 2 ) − 2 1 ( 1 0 2 ) ( sin 1 3 5 ) ≈ 8 2 . 4 5 . So the desired area is 1 5 7 . 0 8 + 8 2 . 4 5 = 2 3 9 . 5 3