Find the coloured area

Geometry Level 3

A B C D ABCD is square and C C is the center of the circle. Given that C E = 10 cm CE = 10\text{ cm} and D E C DEC is a triangle. Find the area of the shaded region (in cm 2 \text{cm}^2 ).

Give your answer to 2 decimal places.


The answer is 239.53.

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3 solutions

The area of the shaded region is equal to the area of a semicircle plus the area of a circular segment. The area of the semicircle is 1 2 π ( 1 0 2 ) 157.08 \dfrac{1}{2}\pi (10^2) \approx 157.08 . The area of the circular segment is equal to the area of the circular sector minus the area of the triangle, we have 135 360 ( π ) ( 1 0 2 ) 1 2 ( 1 0 2 ) ( sin 135 ) 82.45 \dfrac{135}{360}(\pi)(10^2)-\dfrac{1}{2}(10^2)(\sin 135) \approx 82.45 . So the desired area is 157.08 + 82.45 = 239.53 157.08+82.45=\boxed{239.53}

Yahia El Haw
Apr 17, 2016

Marta Reece
May 12, 2018

Area = = Area of circle - area of pie slice D C F DCF- area of triangle D E C DEC .

Area = 100 π 45 360 100 π 2 1 2 10 s i n ( 22.5 ) 10 c o s ( 22.5 ) = 239.53 =100\pi-\frac{45}{360}\cdot100\pi-2\cdot\frac12\cdot10sin(22.5)\cdot 10cos(22.5)=\boxed{239.53}

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