The perimeter of a rhombus of 96 cm and obtuse angle of 1 2 0 ∘ .
Find the lengths of its diagonals.
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Consider the diagram on the left.
By law of cosines, we have
a 2 = 2 4 2 + 2 4 2 − 2 ( 2 4 ) ( 2 4 ) ( cos 1 2 0 ) ⟹ a = 4 1 . 5 7
By law of cosines again, we have
b 2 = 2 4 2 + 2 4 2 − 2 ( 2 4 ) ( 2 4 ) ( cos 6 0 ) ⟹ b = 2 4
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No other calculation apart from dividing 96 into 4 equal side length needed. If the obtuse angle is 120°, then said rhombus must have made up from combining 2 equilateral triangle together, so its shorter diagonal must be 24.