Find the empirical formula

Chemistry Level 1

The empirical formula of a compound is C H X 2 O \ce{CH_2O} . If its empirical weight is equal to its vapor density, calculate the molecular formula of the compound.

C X 3 H X 6 O X 3 \ce{C_3H_6O_3} C H X 2 O \ce{CH_2O} C X 2 H X 4 O X 2 \ce{C_2H_4O_2} C X 4 H X 8 O X 4 \ce{C_4H_8O_4}

Ashish Menon by Ashish Menon , 20, India

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2 solutions

Ashish Menon
Jun 29, 2016

Empirical weight is 12 × 1 + 1 × 2 + 16 = 30 g 12×1 + 1×2 + 16 = 30g .
Now, molecular weight = 2 2 × vapour density = 2 × 30 = 60 g 2×30 = 60g (because empirical weight = vapour density)
And the only option whose molecular weight is 60 g 60g is C X 2 H X 4 O X 2 \color{#3D99F6}{\boxed{\ce{C_2H_4O_2}}} .

2 Helpful 0 Interesting 0 Brilliant 0 Confused

Hey Mr @Ashish Siba.....would you like to post the answer??? why the answer is B???

0 Helpful 0 Interesting 0 Brilliant 0 Confused

Yep I have posted it. Thanks for asking :)

Ashish Menon - 4 years, 11 months ago

lol its damn easy, like answering a first class question

Y Harith - 3 years, 3 months ago

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