Find the exact value

Algebra Level 3

2 + 1 2 + 1 2 + . . . = ? \huge{2+\frac{1}{2+\frac{1}{2+...}}= \ ?}

None of answers shown is correct 0.41421356237 -0.41421356237 1 + 2 1+\sqrt{2} 1 2 1-\sqrt{2} There is no fix value 2.41421356237 2.41421356237

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1 solution

Vu Hoang
Dec 19, 2015

Set 2 + 1 2 + 1 2 + . . . = x 2+\frac{1}{2+\frac{1}{2+...}}=x , so x > = 2 x>=2 .Then 1 2 + 1 2 + . . . = x 2 \frac{1}{2+\frac{1}{2+...}}=x-2 .Flip 2 sides over we got 2 + 1 2 + . . . = 1 x 2 2+\frac{1}{2+...}=\frac{1}{x-2} .Realize the left side of equation is definitely x .Hence, x = 1 x 2 x=\frac{1}{x-2} .We got quadratic equation x 2 2 x 1 = 0 x^2-2x-1=0 .The solution will be 1 + ( 2 ) 1+\sqrt(2)

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