Find the force!

Take g=9.8 m/s^2

Find that force!


The answer is 94.83.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

4 solutions

Ahmed Hassaneen
May 23, 2014

Net Force = 0 , F- f - mgsin(theta) = 0 , F= f+mgsin(theta) F = (0.23)(15)(9.8)cos(26) + (15)(9.8)sin(26) = 94.828 .

Bernardo Sulzbach
Jun 28, 2014

Plugging the following into Wolfram|Alpha

(cos 26°)(15 kg)(0.23)(g)+(sin 26°)(15 kg)(g)

Returns

 94.89 N
Pankaj Kumar
May 27, 2014

F = mgsin(26) + 0.23 * mgcos(26) = 94.92

Hello,

as the speed is constant, acceleration is 0 m/s^2...

F(nett) = 0

F - ( Wx + fk) = 0

F = Wx + fk = (15)(9.81)(sin 26) + (0.23)(15)(9.81)(cos 26)

F = ~ 94.926 N

Thanks yo....

what i did that i took g =10 instead of 9.8

Shashank Rustagi - 6 years ago

Log in to reply

Even i did the same and got 96.76

Vansh Verma - 5 years, 7 months ago

by approximate value....

MOHD NAIM MOHD AMIN - 6 years ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...