Find the Mass

Calculus Level 5

x = r cos ( θ ) y = r sin ( θ ) z = z x = r\cos(\theta)\hspace{1cm}y = r\sin(\theta)\hspace{1cm}z = z 0 r z 0 θ 2 π 0 z 1 0\leq\,r\leq\sqrt{z}\hspace{1cm}0\leq\,\theta\leq2\pi\hspace{1cm}0\leq\,z\leq1

A solid object exists within the standard ( x , y , z ) (x,y,z) coordinate system. Its geometry is parametrized as shown above.

The object has a mass density ρ = e z 2 \large {\rho = e^{z^{2}}} , where e e is Euler's number . The objects mass can be expressed as:

π A ( e B ) , {\dfrac{\pi}{A} (e - B)},

where A A and B B are integers , determine A + B A+B .


The answer is 3.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

2 solutions

First Last
Sep 3, 2016

Using cylindrical coordinates, with the substitutions provided,

x = r cos θ y = r sin θ z = z \displaystyle x = r\cos\theta \quad y = r\sin\theta \quad z = z

we set up a triple integral with the mass function as the integrand. The Jacobian for this variable change is just r r .

mass = 0 1 0 z 0 2 π e z 2 r d θ d r d z = π ( e 1 ) 2 \displaystyle = \int_{0}^{1}\int_{0}^{\sqrt{z}}\int_{0}^{2\pi}e^{z^2}r \quad d\theta dr dz = \boxed{\frac{\pi (e - 1)}{2}}

Steven Chase
Sep 2, 2016

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...