find the measure of the required angle

Geometry Level 1

In A B C \triangle ABC shown above, point D D lies on line A C AC . Given that A B = A D AB=AD and A B C A C B = 3 0 \angle ABC - \angle ACB = 30^\circ , find the measure of C B D \angle CBD in degrees.

1 5 15^\circ 2 0 20^\circ 1 0 10^\circ 1 2 12^\circ 1 8 18^\circ

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1 solution

θ + α = 30 + A C B \theta + \alpha = 30 + \angle ACB

In D C B \triangle DCB ,

180 α + θ + A C B = 180 180-\alpha + \theta + \angle ACB = 180 \implies A C B = α θ \angle ACB = \alpha - \theta

Substitute,

θ + α = 30 + α θ \theta + \alpha = 30 + \alpha - \theta \implies 2 θ = 30 2\theta = 30 \implies θ = 1 5 \theta = \boxed{15^\circ}

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