Find the minimum of a + b a+b

Algebra Level 4

Let a a and b b be positive real numbers such that both x 2 + a x + 2 b = 0 x^2 + ax + 2b = 0 and x 2 + 2 b x + a = 0 x^2+2bx + a = 0 have real roots.

Find the minimum value of a + b a+b .


The answer is 6.

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1 solution

Chew-Seong Cheong
May 15, 2016

For both the equations to have real roots, we have:

{ x 2 + a x + 2 b = 0 a 2 8 b . . . ( 1 ) x 2 + 2 b x + a = 0 4 b 2 4 a b 2 a . . . ( 2 ) \begin{cases} x^2+ax+2b = 0 & \implies a^2 \ge 8b & ...(1) \\ x^2+2bx+a = 0 & \implies 4b^2 \ge 4a \implies b^2 \ge a & ...(2) \end{cases}

( 1 ) 2 : a 4 64 b 2 From ( 2 ) : b 2 a 64 a a 3 64 a 4 ( 2 ) : b 2 4 b 2 a + b 6 \begin{aligned} (1)^2: \quad a^4 & \ge 64\color{#3D99F6}{b^2 \quad \quad \small \text{From }(2): b^2 \ge a} \\ & \ge 64\color{#3D99F6}{a} \\ a^3 & \ge 64 \\ \implies a & \ge 4 \\ (2): \quad \ \ b^2 & \ge 4 \\ \implies b & \ge 2 \\ \implies a + b & \ge \boxed{6} \end{aligned}

I did the same way, are there other methods to do this?

Puneet Pinku - 5 years ago

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Sorry, I can't think of any at the moment.

Chew-Seong Cheong - 5 years ago

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Its okay, but please publish one if you get any. Please notify me also because I will have no means to know whether you have posted or not.

Puneet Pinku - 5 years ago

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