Find the missing digits

3141A92A6 is divisible by 36, if it is also divisible in 4 and 9.

A number is divisible by 4 if the last two digit is divisible by 4.,

4 | 10A+6.

A number is divisible by 9 if the sum of the its digit is divisible by 9

9 | 3+1+4+1+A+9+2+A+6 => 9 | 26 + 2A.

The value of A = {0,1,2,3,4,5,6,7,8,9} which satisfy both 4 | 10A+6 and 9 | 26 + 2A is 5.

Therefore A = 5.

Just noticed that this number has something to do with Pie

• The number should be divisible by 36 (or 2×2×3×3)

• If the last 2 digit of a number is divisible by 4, then the whole number is divisible by 4. (1,3,5,7,9 meet this criteria)

• If the sum of the digits of a number is divisible by 6 and the last digit is even, then the number is divisible by 6 (2,5,8 meet this criteria)

Only 5 is common to those tests.

Proof: 314159256 ÷ 36 = 8726646

This is NOT the digits of Pi. The people making this problem made an error, because no matter where you cut it off, the digits of pi isn't even divisible by any number currently known, but pi, itself. She got the 6 and the 5 backwards. By the way, the easiest way and fastest way to solve this is to just start plugging in number 1 - 9. 5 is the one that works. Ironically, 5 is a prime unlike 6 or 9.

Its the digits of pi

A number is divisible by 36 mean it must be divisible by 9 too. And a number is divisible by 9 only if the sum of all digit of the number is divisible by 9. So here 26 + 2A should be divisible by 9. Only A = 5 satisfy that. So Ans is 5.