The product of the perimeter of a triangle, the radius of its in-circle, and a number gives the area of the triangle. The number is
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Let inradius be r , semiperimeter be s , and area of triangle be Δ .
It is quite well known that r = s Δ
Hence Δ = r s
From given conditions, for a real number k we have 2 r s k = Δ
That means 2 k Δ = Δ
Implying k = 0 . 5