Let the number of solutions of be then find aproximate value of
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One way to solve this problem is to take logs of both sides of the original equation to obtain x = l n x 4 . Now if one differentiates both sides with respect to x we now get 1 = 4 / x , which the logarithmic curve has a tangent line that's parallel to y = x at x = 4 . This tangent line is expressible as y − l n 2 5 6 = x − 4 , or y = x + ( l n 2 5 6 − 4 ) which runs parallel and above y = x .
Since the point ( x , y ) = ( 4 , l n 2 5 6 ) lies above ( 4 , 4 ) , there exists two points ( a , a ) and ( b , b ) on the line y = x which are intersection points with y = l n x 4 (by the Mean-Value Theorem). Since the logarithmic curve grows at a more slower rate than the linear function (i.e. 1 > 4 / x for x = [ b , ∞ ) , there are no more intersection points to be found.
Thus, n = 2 and e 2 + e = 1 0 . 1 0 .