The sum of an arithmetic progression is . If the and terms are and , respectively, find the number of terms of this progression.
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
Relevant wiki: Arithmetic Progressions
Using the formula a n = a m + ( n − m ) d , we have
− 1 5 5 = − 3 5 + ( 1 0 − 2 ) d ⟹ d = − 1 5
Using again the formula, we have
a 1 = − 3 5 + ( 1 − 2 ) ( − 1 5 ) = − 2 0
Using the formula s = 2 n [ 2 a 1 + ( n − 1 ) d ] , we have
− 1 6 4 5 = 2 n [ 2 ( − 2 0 ) + ( n − 1 ) ( − 1 5 ) ]
Simplifying this will end in a quadratic equation
1 5 n 2 + 2 5 n − 3 2 9 0 = 0
Using any method to solve for n , we find that n = 1 4 .