The terms being added on the left side of the above equation form an arithmetic progression in that order.
What is
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Use the formula s = 2 n [ 2 a 1 + ( n − 1 ) d ]
6 8 2 1 0 = 2 n [ 2 ( 1 3 ) + ( n − 1 ) ( 1 5 ) ]
1 3 6 4 2 0 = n ( 1 5 n + 1 1 )
1 3 6 4 2 0 = 1 5 n 2 + 1 1 n
1 5 n 2 + 1 1 n − 1 3 6 4 2 0 = 0
By using the quadratic formula, we get n = 9 5 .