Find the numbers

Number Theory Level 1

If A , B , C A, B, C all are different positive integer numbers and A + B + C = A × B × C A+B+C = A×B×C , then what is the resultant value of A + B + C A+B+C ?


The answer is 6.

Zakir Dakua by Zakir Dakua , 37, Bangladesh

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Chew-Seong Cheong
Dec 16, 2015

The three positive integers are 1 1 , 2 2 and 3 3 for 1 + 2 + 3 = 1 × 2 × 3 = 6 1+2+3 = 1\times 2 \times 3 = \boxed{6} .

3 Helpful 0 Interesting 0 Brilliant 0 Confused

Is there only one such triplet ?

Akshat Sharda - 5 years, 6 months ago

Log in to reply

I don't have the answer.

Chew-Seong Cheong - 5 years, 6 months ago

Every perfect number can be written like that, but only 6 has exactly three divisors

Joseph Johannes - 5 years, 2 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...