Find the orange area!

Geometry Level 2

Three squares of side lengths 8 8 , 12 12 , and 10 10 are placed side-by-side as shown. Find the area of the orange region.


The answer is 70.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

3 solutions

Chew-Seong Cheong
May 24, 2020

Redraw the figure above without affecting the orange region. We find the orange region is given by:

A = 30 × 12 30 × 10 2 20 × 12 2 10 × 2 = 360 150 120 20 = 70 \begin{aligned} A & = 30 \times 12 - \frac {30\times 10}2 - \frac {20\times 12}2 - 10 \times 2 \\ & = 360 - 150 - 120 - 20 = \boxed {70} \end{aligned}

Excellent, Sir!

Vinayak Srivastava - 1 year ago

Though i calculated each area of trapezium using analytic geometry of slopes and all, your's is much more clean, Nice!

Mahdi Raza - 1 year ago

Log in to reply

I did not know how to solve it even though I posted it! :)

Vinayak Srivastava - 1 year ago
Steven Chase
May 23, 2020

Define the points as shown and use the cross product formula for the area of a triangle. Calculate the areas of the two sub-triangles as shown, and combine them. The area comes out to 70 70 .

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
import math

x1 = 20.0
y1 = 12.0

x2 = 20.0
y2 = 10.0

x3 = 30.0
y3 = 10.0

A1 = 0.5*math.fabs(x1*y2 - y1*x2)
A2 = 0.5*math.fabs(x2*y3 - y2*x3)

A = A1 + A2

print A
# 70.0

Nice solution but I was thinking that if it is possible to find a solution only by elementary geometry?

Vinayak Srivastava - 1 year ago

Log in to reply

Yes, you can also do:

A = 1 2 ( 10 ) ( 10 ) + 1 2 ( 2 ) ( 20 ) = 70 A = \frac{1}{2} (10)(10) + \frac{1}{2} (2)(20) = 70

Steven Chase - 1 year ago

Log in to reply

Thanks a lot! This problem was confusing me too much.

Vinayak Srivastava - 1 year ago

Area of figure = a r ( A B C ) ar(ABC) + a r ( C B D ) ar(CBD) - a r ( g r e e n r e c t a n g l e ) ar(green rectangle)

Area of figure = 1 2 10 12 + 1 2 2 30 10 2 \frac{1}{2}*10*12 + \frac{1}{2}*2*30-10*2

Area of figure = 70 \boxed{70}

Log in to reply

Nice solution!

Vinayak Srivastava - 11 months, 2 weeks ago

Log in to reply

@Vinayak Srivastava ,the previous solution was wrong.

A Former Brilliant Member - 11 months, 1 week ago

Thanks.How you have done it ?.

A Former Brilliant Member - 11 months, 2 weeks ago

Log in to reply

I did not do it :) I did not know I how to do it, actually.

Vinayak Srivastava - 11 months, 2 weeks ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...