Find the original dimensions

Algebra Level pending

If the smaller dimension of a rectangle is increased by 3 3 meters and the larger dimension by 5 5 meters, one dimension becomes 3 5 \dfrac{3}{5} of the other, and the area is increased by 135 135 square meter. Find the original dimensions of the rectangle.

20 m × 25 m 20~m \times 25~m 12 m × 20 m 12~m \times 20~m 12 m × 25 m 12~m \times 25~m 20 m × 15 m 20~m \times 15~m

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1 solution

Jerry McKenzie
Dec 28, 2017

Carefully reading the problem, let x be the original smaller dimension and y be the original larger dimension. It follow these two equations:

3 5 = x + 3 y + 5 3 y + 15 = 5 x + 15 3 y = 5 x \quad \frac{3}{5}=\frac{x+3}{y+5} \Rightarrow 3y+15=5x+15 \Rightarrow 3y=5x

( x + 3 ) ( y + 5 ) x y = 135 x y + 5 x + 3 y + 15 x y = 135 5 x + 3 y = 120 \quad (x+3)(y+5)-xy=135 \Rightarrow xy+5x+3y+15-xy=135 \Rightarrow 5x+3y=120

Using a substitution with 3 y = 5 x 3y=5x into the second equation, we get to:

5 x + 3 y = 120 5 x + 5 x = 120 x = 12 \quad 5x+3y=120 \Rightarrow 5x+5x=120 \Rightarrow x=12

going back to equation 1, using x=12, we get:

3 y = 5 x 3 y = 5 12 y = 20 \quad 3y=5x \Rightarrow 3y=5\cdot 12 \Rightarrow y=20

All of this was done with meters being the understood units. :)

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