Find the original number

Algebra Level pending

The sum of the digits of a certain integer having two digits is 11. If the digits are reversed, the new number is 7 greater than twice the original number. Find the original number.


The answer is 38.

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1 solution

Let u u be the units digit and t t be the tens digit, then we have the two equations

u + t = 11 u+t=11

10 u + t = 2 + 2 ( 10 t + u ) 10u+t=2+2(10t+u)

Solving these two simultaneous two equations we get u = 8 u=8 and t = 3 t=3 . So the number is 10 ( 3 ) + 8 = 38 10(3)+8=\boxed{38}

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