The sum of the digits of a certain integer having two digits is 11. If the digits are reversed, the new number is 7 greater than twice the original number. Find the original number.
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Let u be the units digit and t be the tens digit, then we have the two equations
u + t = 1 1
1 0 u + t = 2 + 2 ( 1 0 t + u )
Solving these two simultaneous two equations we get u = 8 and t = 3 . So the number is 1 0 ( 3 ) + 8 = 3 8