Find the perimeter

Let the side lengths of the rectangle be $a$ and $b$ . Then, the area $ab = \dfrac {4035}8$ , the diagonal length $\sqrt{a^2+b^2} = \dfrac {2017}2$ and the parameter

$\begin{aligned} p & = 2(a+b) \\ p^2 & = 4(a+b)^2 \\ & = 4(a^2 + 2ab + b^2) \\ & = 4 \left[\left(\frac {2017}2 \right)^2 + 2 \times \frac {4035}8 \right] \\ & = 4 \times \frac {2017^2 + 4035}4 \\ & = 2017^2 + 2(2017) + 1 \\ & = (2017+1)^2 \\ \implies p & = \boxed{2018} \end{aligned}$

Let the sides of the rectangle be 'a' and 'b' | Given , area of rectangle = ab = 4035/8 | Diagonal of rectangle = √(a^2+b^2) = 2017/2 | Therefore , a^2 + b^2 = 2017^2/4 | We know , (a+b)^2 = a^2 + b^2 + 2ab | (a+b)^2= 2017^2/4 + 4035/4 | a+b = 1/2 √(2017^2 + 4035) | 2(a+b) = √(4068289 + 4035) | Perimeter of rectangle = √4072324 = 2018 || I have included tough calculations in the solution. Is there any other method which is easier and requires less calculation?