Find the PH:-
Chemistry
Level
2
calculate the ph of a solution containing 0.01 moles of H2SO4 and 0.01 moles of KOH in 2 litre water..
The answer is 2.301.
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1 solution
ph = -log {H+} in this question we have 0.01moles of H2So4which means 0.02 H+ions... and we hav 0.01 moles of KOH which means 0.01 OH-ions.... so 0.01 moles of H+will neutralise 0.01 moles of OH- ... At last we have 0.01 moles of H+ In 2litre solution M=n/v M=0.01/2=0.005 molar H+ Answer=--log [H+] =--log [0.005] =2.3011