\( Find\,\,two\,\,real\,\,matrices\,\,M,\,\,N\,\,with \\ M^2+N^2=\left( \begin{matrix} 2& 3\\ 3& 2\\ \end{matrix} \right) \\ Bonus:\,\,Show\,\,that\,\,if\,\,M,\,\,N\,\,are\,\,real\,\,matrices\,\,with \\ M^2+N^2=\,\,\left( \begin{matrix} 2& 3\\ 3& 2\\ \end{matrix} \right) \,\,then\,\,MN\ne NM
\)
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A minor typo in the second line, it should be M ( a ) 2 + ( M ( a ) T ) 2
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If M ( a ) is the matrix M ( a ) = ( 1 0 a 1 ) then M ( a ) 2 = M ( 2 a ) , and hence M ( a ) 2 + ( M ( a ) T ) 2 = M ( 2 a ) + M ( 2 a ) T = ( 2 2 a 2 a 2 ) so, for this question, we want M = M ( 2 3 ) and N = M T .
If M , N are real matrices such that M 2 + N 2 = ( 2 3 3 2 ) and M N = N M , then Z = M + i N is a complex matrix such that Z Z = ( 2 3 3 2 ) , which implies that ∣ ∣ d e t Z ∣ ∣ 2 = d e t Z × d e t Z = d e t ( 2 3 3 2 ) = − 5 which is not possible.