How many positive integers are multiples of and have divisors?
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-The prime factorization of a number with exactly 1 5 positive divisors is a 2 × b 4 or c 14 with a ; b ; c prime numbers because the + 1 exponent product must be 1 5 and the only 1 5 factoring is: 3 × 5 a n d 1 × 1 5 .
-The fact that this number is a multiple of 1 5 implies that the prime factors component 1 5 , namely 3 and 5 , also make up this number. Hence the only corresponding numbers are 3 2 × 5 4 = 5 6 2 5 and 3 4 × 5 2 = 2 0 2 5 .