In a cricket match, Team A scored 232 runs without losing a wicket. The score consisted of byes, wides and runs scored by two opening batsmen: Ram and Shyam. The runs scored by the two batsmen are 26 times wides. There are 8 more byes than wides. If the ratio of the runs scored by Ram and Shyam is 6:7, then the runs scored by Ram is:
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Let the number of runs scored by byes, wides and runs be x, y and z respectively: x+y+z=232 -------- (i)
The runs scored by the two batsmen are 26 times the wides: z=26y --------- (ii)
There are 8 more byes than wides: x=y+8 -------- (iii)
Substituting equations (iii) and (ii) in equation (i), we get, y=8,z=208
The runs scored by Ram and Shyam were in the ratio 6 : 7 Let the runs scored by Ram be 6r and by Shyam be 7r. 13r=208 ⇒ r=16 Runs scored by Ram =16×6= 96