Find the shaded area

Geometry Level 1

In the figure to the right, P Q R S T U PQRSTU is a regular hexagon.

Sides P Q , R S , PQ, RS, and T U TU are extended to form triangle A B C ABC .

If the area of triangle A B C ABC is 90, then find the area of the shaded region.

6 6 9 9 10 10 15 15

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11 solutions

Chew-Seong Cheong
Feb 21, 2017

It can be easily seen from the figure above that the shaded region A P U \triangle APU is one of the nine equilateral triangles with side length of the hexagon. Since area of A B C \triangle ABC is 90, the area of A P U \triangle APU is 90 9 = 10 \dfrac {90}9 = \boxed{10} .

@Pi Han Goh @Ojasee Duble @Chew-Seong Cheong @Peter van der Linden

Thanks. I had cleaned up the phrasing of the problem to make it clear that the vertices of the hexagon lie on the sides of the triangle. I understand it can be frustrating having to infer the intentions of the problem creator.

I've cleared out the comment chain about "It assumed that the positions of P,Q,R,S,T,U are specified, which is not". Sorry for the confusion.

Calvin Lin Staff - 4 years, 3 months ago

Nice visual solution!! :-D

Ojasee Duble - 4 years, 3 months ago

i divided the hexagon into 6 equalateral triangles ,plus the 3 extendeded ones ,giving 9 altogether ,one ninth of 90 = 10 !

Seamus Cormack - 4 years, 3 months ago

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Yup, the key point is to identify that we can divide A B C \triangle ABC into nine triangles congruent to A P U \triangle APU , so they will all have the same area.

Pranshu Gaba - 4 years, 3 months ago

That's how I solved it! Nice.

Hunter Edwards - 4 years, 2 months ago

I did that but I skipped the diagram step. Its an equalateral triangle so that helps. I just visualised...

Zoe Codrington - 2 years, 9 months ago

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Then I saw that the sides were divided into thirds, so I did 1/3x1/3=1/9

Zoe Codrington - 2 years, 9 months ago

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1/9 if triangle ABC that is. Or 90/9=10

Zoe Codrington - 2 years, 9 months ago
Venkatachalam J
Feb 26, 2017

Relevant wiki: Length and Area Problem Solving

Given that it is regular hexagon. Hexagon has 6 equilateral triangle. while extend it we will get three more same equilateral triangle.

The shaded region = 1 9 \frac{1}{9} and the total area =90

Therefore, the Area of the shaded region = 90 9 \frac{90}{9} =10

Are all the nine triangles in this figure of equal area? How do we know?

Agnishom Chattopadhyay - 4 years, 3 months ago

Agnishom is right. For completeness, you need to state why all the 9 triangles are of equal area. Do you know how to do that?

Pi Han Goh - 4 years, 3 months ago

@Agnishom Chattopadhyay & @Pi Han Goh I modified the diagram and added the required inputs. Hope now it will be clear.

Venkatachalam J - 4 years, 3 months ago

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Yup! It works now! Great~~

Pi Han Goh - 4 years, 3 months ago
Naren Bhandari
Feb 26, 2017

Since the interior angle of regular hexgon is 12 0 120^\circ and on calculating the each interior triangle is 18 0 12 0 = > 60 ° 180^\circ - 120^\circ => 60° This shows are triangle are equilateral moreover, triangle A B C ABC is also an equilateral triangle.

Let the total length of triangle ABC be A. Then

3 4 A 2 = 90 \frac{\sqrt3}{4} A^2 = 90

If s be the side length of small triangle. Then A = 3 s A = 3s Plugging A = 3 s A= 3s in above equation

3 4 ( 3 s ) 2 = 90 \frac{\sqrt3}{4}(3s)^2 = 90

3 4 s 2 = 10 \frac{\sqrt3}{4}s^2 = \boxed{10}

Where do you get 3 4 A 2 = 90 \frac{\sqrt{3}}{4}A^2=90 ? What formula is that?

Christopher Boo - 4 years, 3 months ago

It's the formula to calculate the area of an equilateral triangle. where A ( assumed) is the length of the equilateral triangle

Naren Bhandari - 4 years, 3 months ago

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I see. You could mention that in your solution to clear things up! :)

Christopher Boo - 4 years, 3 months ago

Thank you for the advice. :)

Naren Bhandari - 4 years, 3 months ago

Since all the triangles are equilateral they all have the same area and so the answer becomes like this:

Total area of the triangle Number of triangles \frac{\text{Total area of the triangle}}{\text{Number of triangles}} = area of a single triangle

So 90 9 \frac{90}{9} = 10

Good job! The key point is to understand that A P U \triangle APU is an equilateral triangle, and that A B C \triangle ABC can be divided into 9 triangles congruent to A P U \triangle APU

Pranshu Gaba - 4 years, 3 months ago

Yeah exactly!

Syed Hamza Khalid - 4 years, 3 months ago

Can you plz upvote my solution

Syed Hamza Khalid - 4 years, 3 months ago
Lance Fernando
Mar 4, 2017

Triangles BQR, STC, and PAU are of the same area. Their total area comprises 1/3 of the area of the overall triangle, as a hexagon is equivalent to 6 small triangles here, comprising 2/3 of the area of the overall triangle. To find a small triangle's area, set up the equation as follows: 9a = 90. "a" is the area of the small triangle indicated on the illustration -- solving for it gives us 10.

Yuppers~ This is correct.

Isn't it fascinating that a regular hexagon can fit 6 non-overlapping equilateral triangles? I wonder which other regular n n -gon has this equivalent property as well....

Pi Han Goh - 4 years, 3 months ago

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I might try to experiment on which n-gons can fit non-overlapping equilateral triangles; but so far, only the hexagon had this property. Who knows that we can derive a formula for that?

Lance Fernando - 4 years, 3 months ago
Dinamani Borah
Mar 3, 2017

This is a valid solution. I appreciate the fact that you carefully proved that the triangle is indeed equilateral

Agnishom Chattopadhyay - 4 years, 3 months ago

It is it hard to prove that the three triangles that are cut off are equilateral. Let's say the length of the side of the given triangle is x, then the length of PU is obviously 1 3 \frac 13 x. So the area of triangle PUA is ( 1 3 ) 2 90 = 10 (\frac {1}{3})^2 \cdot 90 = 10 .

It would be great if you showed why the triangles cut off are equilateral. It will help others who cannot solve this problem understand your solution better.

Pranshu Gaba - 4 years, 3 months ago

they are equilateral because the interior angles of the hexagon are each 120 degrees, making the adjacent angle 60. If two angles of a triangle are 60, the third angle is 60. equilateral.

Terry Townsend - 4 years, 3 months ago

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That is indeed valid reasoning

Agnishom Chattopadhyay - 4 years, 3 months ago

It's pretty obvious for me...

Zoe Codrington - 2 years, 9 months ago
Vivek Kudipudi
Feb 26, 2017

Make 9 triangles and divide it equally

Can you elaborate more on how to make 9 triangles?

Christopher Boo - 4 years, 3 months ago
Terry Townsend
Mar 2, 2017

I got 10 by using the formula for area of an equilateral triangle. A=1/4(root3) times side squared. I used 3s for a side and solved for s (one side of the small equilateral triangles. Then I used s to calculate the area of one of the small triangles.

Why is the side of the smaller triangle exactly a third of the larger triangle?

Agnishom Chattopadhyay - 4 years, 3 months ago
Norton Kapp
Mar 1, 2017

There are 9 triangles inside of hexagon

I do not see why. Can you explain?

Agnishom Chattopadhyay - 4 years, 3 months ago
Paul Snowdon
Feb 28, 2017

Triangle ABC is scale factor x3 of triangle APU. This means, area of ABC is 'scale factor squared' of area APU. Let area APU = y and area ABC = 90 (given). So, y x 3x3 = 90; hence y = 90/9 = 10.

This is indeed a valid intuition and is a great way to solve the problem

However, it remains to check that A B C ABC is really a scale 3 factor of A P U APU . And that the area of the scaled triangle varies with the square of the side lengths.

Agnishom Chattopadhyay - 4 years, 3 months ago

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